What would be the voltage across a 50-ohm dummy load dissipating 1,200 watts?

Study for the Federal Communications Commission (FCC) Element 3 Test. Use flashcards and multiple choice questions with hints and explanations. Get prepared for your exam today!

To determine the voltage across a 50-ohm dummy load that is dissipating 1,200 watts, the relationship between power (P), voltage (V), and resistance (R) can be utilized. The formula for power in an electrical circuit is given by:

[ P = \frac{V^2}{R} ]

Rearranging this formula to solve for voltage gives:

[ V = \sqrt{P \times R} ]

Substituting in the values of power (1,200 watts) and resistance (50 ohms):

[ V = \sqrt{1,200 \text{ W} \times 50 \text{ ohms}} ]

Calculating this yields:

[ V = \sqrt{60,000} ]

[ V \approx 245 \text{ volts} ]

Therefore, the voltage across the dummy load is approximately 245 volts, making this the correct choice. This calculation effectively demonstrates how to relate the power dissipated by the dummy load to the voltage across it based on its resistance.

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