What is the output peak envelope power from a transmitter as measured on an oscilloscope showing 200 volts peak-to-peak across a 50-ohm load resistor?

To calculate the output peak envelope power (PEP) from a transmitter, you can use the formula related to voltage and load resistance. The peak voltage measured across the load is given as 200 volts peak-to-peak. To find the peak voltage (Vp), you first need to convert the peak-to-peak voltage into peak voltage. This is done by dividing the peak-to-peak voltage by 2:

Vp = 200 Vpp / 2 = 100 Vp (peak voltage)

Next, to calculate the power in watts (P), you can use the formula:

P = (Vp²) / R

Where Vp is the peak voltage and R is the resistance. Plugging in the numbers:

P = (100 V)² / 50 ohms

This simplifies to:

P = 10,000 / 50

P = 200 watts

Therefore, the output peak envelope power from the transmitter, as measured across a 50-ohm load resistor, is 200 watts. This aligns with the calculated value.

The other answer choices represent different calculations, but based on the given voltage and resistance, the power calculation correctly identifies 200 watts as the peak envelope power.