What is the maximum deviation from a frequency reading of 462,100,000 Hertz with a time base accuracy of ± 1.0 ppm?

To determine the maximum deviation from a frequency reading of 462,100,000 Hertz with a time base accuracy of ± 1.0 parts per million (ppm), we start by calculating the deviation in Hertz.

First, we convert the frequency to parts per million. The formula to find the maximum deviation in Hertz is:

[

\text{Deviation (Hz)} = \text{Frequency (Hz)} \times \frac{\text{ppm}}{1,000,000}

]

In this case:

[

\text{Deviation (Hz)} = 462,100,000 , \text{Hz} \times \frac{1.0}{1,000,000}

]

Calculating this gives:

[

\text{Deviation (Hz)} = 462.1 , \text{Hz}

]

This means that with a time base accuracy of ± 1.0 ppm, the frequency can deviate by a maximum of 462.1 Hz above or below the base frequency of 462,100,000 Hz. Thus, the maximum deviation is 462.1 Hz.

The correct answer reflects this calculation, clearly indicating that the maximum deviation aligns with the calculated value of 462