What is the impedance of a network composed of a 400-ohm-reactance capacitor in series with a 300-ohm resistor, expressed in polar coordinates?

In this scenario, the network consists of a resistor and a capacitor connected in series. The impedance of a resistor (R) is purely real, while the impedance of a capacitor (Z_C) introduces a reactive (imaginary) component. The impedance of the capacitor can be expressed as -jX_C, where X_C is positive for the capacitive reactance.

Here we have a resistor with an impedance of 300 ohms and a capacitor with a reactance of 400 ohms. When these elements are connected in series, their impedances combine vectorially, as follows:

1. The impedance of the resistor is 300 ohms (real part).

2. The impedance of the capacitor is -j400 ohms (imaginary part).

Adding these gives:

• Real part: 300 ohms

• Imaginary part: -400 ohms

To find the total impedance in polar form, you first need to calculate the magnitude and the angle of the resulting complex impedance:

1. Magnitude (|Z|) is calculated using the formula:

[

|Z| = \sqrt{(R^2 + X^2)} = \sqrt{(300^2 + (-400)^2)} = \sqrt