What is the conductance (G) of a circuit when 6 amperes of current flow with a 12 volts DC applied?

Study for the Federal Communications Commission (FCC) Element 3 Test. Use flashcards and multiple choice questions with hints and explanations. Get prepared for your exam today!

To determine the conductance (G) of a circuit, we can use the relationship between conductance, current (I), and voltage (V). Conductance is defined as the reciprocal of resistance (R) and can also be expressed as:

[ G = \frac{I}{V} ]

Where:

  • G is the conductance in Siemens (S)

  • I is the current in amperes (A)

  • V is the voltage in volts (V)

In this scenario, we have a current of 6 amperes flowing under a voltage of 12 volts. By substituting the values into the formula, we get:

[ G = \frac{6 , \text{A}}{12 , \text{V}} = 0.5 , \text{S} ]

Therefore, the conductance of the circuit is 0.5 Siemens. This indicates that the circuit can conduct 0.5 amperes per volt, which is a measure of how easily electricity can flow through the circuit under the given conditions.

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